You're right, I'm not sure why on earth I was test m instead of f_xm for the condition, but I've fixed that. I made some modifications last night, after I posted actually. Method: Bisectional (closed domain) (a single root)! This fortran 90 program implements Bisection method to find the root. Program main! Format(' no roots for Bisectional method') 105 format(' f(root) = ',1pe12.5) end program. This may cause you grief (like an infinite loop for some pairs ). I note that you don't do any preliminary testing to see that the interval actually contains a zero. Surely if you're looking for a root you want the value of the function f(m) to approach zero, not the value of m m is simply the midpoint x-value, which takes on values in your search interval. What is the value of m the first time the DO condition is tested (that is, what is its value just prior to entering the DO loop for the first time? Propaganda Duel Midi File. F_xa = SIN(a) f_xb = SIN(b) f_xm = SIN(m) IF (ABS(m) 0) THEN a= m ELSE IF (f_xa*f_xm. The attempt at a solution program bisec IMPLICIT NONE REAL:: a, b, m, f_xa, f_xb, f_xm WRITE (*,*) 'Please enter the interval :' READ (*,*) a,b DO! Starsat 2200 Hd Wifi Security. ![]() The intervals are input by the user, and then the do loop continues until the condition (m becomes very close to 0 or equals 0) is met. ![]() ![]() The problem statement, all variables and given/known data The purpose of this program is to calculate the approximate roots of the Sine function on given intervals.
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